Solve the System of Equations y-x=6 y+x=-10

$y - x = 6$ $y + x = - 10$

Add $x$ to both sides of the equation.

$y = 6 + x$

$y + x = - 10$

Replace all occurrences of $y$ with $6 + x$ in each equation.

Replace all occurrences of $y$ in $y + x = - 10$ with $6 + x$ .

$(6 + x) + x = - 10$

$y = 6 + x$

Simplify the left side.

Add $x$ and $x$ .

$6 + 2 x = - 10$

$y = 6 + x$

$6 + 2 x = - 10$

$y = 6 + x$

$6 + 2 x = - 10$

$y = 6 + x$

Solve for $x$ in $6 + 2 x = - 10$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $6$ from both sides of the equation.

$2 x = - 10 - 6$

$y = 6 + x$

Subtract $6$ from $- 10$ .

$2 x = - 16$

$y = 6 + x$

$2 x = - 16$

$y = 6 + x$

Divide each term in $2 x = - 16$ by $2$ and simplify.

Divide each term in $2 x = - 16$ by $2$ .

$\frac{2 x}{2} = \frac{- 16}{2}$

$y = 6 + x$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 16}{2}$

$y = 6 + x$

Divide $x$ by $1$ .

$x = \frac{- 16}{2}$

$y = 6 + x$

$x = \frac{- 16}{2}$

$y = 6 + x$

$x = \frac{- 16}{2}$

$y = 6 + x$

Simplify the right side.

Divide $- 16$ by $2$ .

$x = - 8$

$y = 6 + x$

$x = - 8$

$y = 6 + x$

$x = - 8$

$y = 6 + x$

$x = - 8$

$y = 6 + x$

Replace all occurrences of $x$ with $- 8$ in each equation.

Replace all occurrences of $x$ in $y = 6 + x$ with $- 8$ .

$y = 6 - 8$

$x = - 8$

Simplify $y = 6 - 8$ .

Simplify the left side.

Remove parentheses.

$y = 6 - 8$

$x = - 8$

$y = 6 - 8$

$x = - 8$

Simplify the right side.

Subtract $8$ from $6$ .

$y = - 2$

$x = - 8$

$y = - 2$

$x = - 8$

$y = - 2$

$x = - 8$

$y = - 2$

$x = - 8$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 8, - 2)$

The result can be shown in multiple forms.

Point Form:

$(- 8, - 2)$

Equation Form:

$x = - 8, y = - 2$

Solve the System of Equations y-x=6 y+x=-10

Related Questions

Support LCMGCF.com by disabling your adblocker.