Write in Exponential Form 2 = log base 8 of 64

$2 = \log_{8} (64)$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 8$ , $x = 64$ , and $y = 2$ .

$b = 8$