Write in Exponential Form log base 4y of 128=x

$\log_{4 y} (128) = x$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 4 y$ , $x = 128$ , and $y = x$ .

$b = 4 y$