Write in Exponential Form log base (x+3) of x+6=2

$\log_{(x + 3)} (x + 6) = 2$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = x + 3$ , $x = x + 6$ , and $y = 2$ .