Write in y=mx+b Form -10x=1-8y

$- 10 x = 1 - 8 y$

Step 1

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Step 2

Rewrite in slope-intercept form.

Rewrite the equation as $1 - 8 y = - 10 x$ .

$1 - 8 y = - 10 x$

Subtract $1$ from both sides of the equation.

$- 8 y = - 10 x - 1$

Divide each term in $- 8 y = - 10 x - 1$ by $- 8$ and simplify.

Divide each term in $- 8 y = - 10 x - 1$ by $- 8$ .

$\frac{- 8 y}{- 8} = \frac{- 10 x}{- 8} + \frac{- 1}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 y}{- 8} = \frac{- 10 x}{- 8} + \frac{- 1}{- 8}$

Divide $y$ by $1$ .

$y = \frac{- 10 x}{- 8} + \frac{- 1}{- 8}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 10$ and $- 8$ .

Factor $- 2$ out of $- 10 x$ .

$y = \frac{- 2 (5 x)}{- 8} + \frac{- 1}{- 8}$

Cancel the common factors.

Factor $- 2$ out of $- 8$ .

$y = \frac{- 2 (5 x)}{- 2 (4)} + \frac{- 1}{- 8}$

Cancel the common factor.

$y = \frac{- 2 (5 x)}{- 2 \cdot 4} + \frac{- 1}{- 8}$

Rewrite the expression.

$y = \frac{5 x}{4} + \frac{- 1}{- 8}$

Dividing two negative values results in a positive value.

$y = \frac{5 x}{4} + \frac{1}{8}$

Reorder terms.

$y = \frac{5}{4} x + \frac{1}{8}$