Solve for b a-b=c

$a - b = c$

Step 1

Subtract $a$ from both sides of the equation.

$- b = c - a$

Step 2

Divide each term in $- b = c - a$ by $- 1$ and simplify.

Divide each term in $- b = c - a$ by $- 1$ .

$\frac{- b}{- 1} = \frac{c}{- 1} + \frac{- a}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{b}{1} = \frac{c}{- 1} + \frac{- a}{- 1}$

Divide $b$ by $1$ .

$b = \frac{c}{- 1} + \frac{- a}{- 1}$

Simplify the right side.

Simplify each term.

Move the negative one from the denominator of $\frac{c}{- 1}$ .

$b = - 1 \cdot c + \frac{- a}{- 1}$

Rewrite $- 1 \cdot c$ as $- c$ .

$b = - c + \frac{- a}{- 1}$

Dividing two negative values results in a positive value.

$b = - c + \frac{a}{1}$

Divide $a$ by $1$ .

$b = - c + a$