Solve for k -3(5k+3)=-6k

$- 3 (5 k + 3) = - 6 k$

Simplify $- 3 (5 k + 3)$ .

Start simplifying.

$0 + 0 - 3 (5 k + 3) = - 6 k$

Simplify by adding zeros.

$- 3 (5 k + 3) = - 6 k$

Apply the distributive property.

$- 3 (5 k) - 3 \cdot 3 = - 6 k$

Multiply.

Multiply $5$ by $- 3$ .

$- 15 k - 3 \cdot 3 = - 6 k$

Multiply $- 3$ by $3$ .

$- 15 k - 9 = - 6 k$

Move all terms containing $k$ to the left side of the equation.

Add $6 k$ to both sides of the equation.

$- 15 k - 9 + 6 k = 0$

Add $- 15 k$ and $6 k$ .

$- 9 k - 9 = 0$

Add $9$ to both sides of the equation.

$- 9 k = 9$

Divide each term in $- 9 k = 9$ by $- 9$ and simplify.

Divide each term in $- 9 k = 9$ by $- 9$ .

$\frac{- 9 k}{- 9} = \frac{9}{- 9}$

Simplify the left side.

Cancel the common factor of $- 9$ .

Cancel the common factor.

$\frac{- 9 k}{- 9} = \frac{9}{- 9}$

Divide $k$ by $1$ .

$k = \frac{9}{- 9}$

Simplify the right side.

Divide $9$ by $- 9$ .

$k = - 1$