Solve for n -10-n^3=-88

$- 10 - n^{3} = - 88$

Step 1

Move all terms not containing $n$ to the right side of the equation.

Add $10$ to both sides of the equation.

$- n^{3} = - 88 + 10$

Add $- 88$ and $10$ .

$- n^{3} = - 78$

Step 2

Divide each term in $- n^{3} = - 78$ by $- 1$ and simplify.

Divide each term in $- n^{3} = - 78$ by $- 1$ .

$\frac{- n^{3}}{- 1} = \frac{- 78}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{n^{3}}{1} = \frac{- 78}{- 1}$

Divide $n^{3}$ by $1$ .

$n^{3} = \frac{- 78}{- 1}$

Simplify the right side.

Divide $- 78$ by $- 1$ .

$n^{3} = 78$

Step 3

Take the cube root of both sides of the equation to eliminate the exponent on the left side.

$n = \sqrt[3]{78}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$n = \sqrt[3]{78}$

Decimal Form:

$n = 4.27265868 \dots$