Solve for x 12x+2(6+7(x+1))=0

$12 x + 2 (6 + 7 (x + 1)) = 0$

Step 1

Simplify $12 x + 2 (6 + 7 (x + 1))$ .

Simplify each term.

Simplify each term.

Apply the distributive property.

$12 x + 2 (6 + 7 x + 7 \cdot 1) = 0$

Multiply $7$ by $1$ .

$12 x + 2 (6 + 7 x + 7) = 0$

$12 x + 2 (6 + 7 x + 7) = 0$

Add $6$ and $7$ .

$12 x + 2 (7 x + 13) = 0$

Apply the distributive property.

$12 x + 2 (7 x) + 2 \cdot 13 = 0$

Multiply $7$ by $2$ .

$12 x + 14 x + 2 \cdot 13 = 0$

Multiply $2$ by $13$ .

$12 x + 14 x + 26 = 0$

$12 x + 14 x + 26 = 0$

Add $12 x$ and $14 x$ .

$26 x + 26 = 0$

$26 x + 26 = 0$

Step 2

Subtract $26$ from both sides of the equation.

$26 x = - 26$

Step 3

Divide each term in $26 x = - 26$ by $26$ and simplify.

Divide each term in $26 x = - 26$ by $26$ .

$\frac{26 x}{26} = \frac{- 26}{26}$

Simplify the left side.

Cancel the common factor of $26$ .

Cancel the common factor.

$\frac{26 x}{26} = \frac{- 26}{26}$

Divide $x$ by $1$ .

$x = \frac{- 26}{26}$

$x = \frac{- 26}{26}$

$x = \frac{- 26}{26}$

Simplify the right side.

Divide $- 26$ by $26$ .

$x = - 1$

$x = - 1$

$x = - 1$

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