Solve the Inequality for x x+3<4x-3

$x + 3 < 4 x - 3$

Step 1

Move all terms containing $x$ to the left side of the inequality.

Subtract $4 x$ from both sides of the inequality.

$x + 3 - 4 x < - 3$

Subtract $4 x$ from $x$ .

$- 3 x + 3 < - 3$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$- 3 x < - 3 - 3$

Subtract $3$ from $- 3$ .

$- 3 x < - 6$

Step 3

Divide each term in $- 3 x < - 6$ by $- 3$ and simplify.

Divide each term in $- 3 x < - 6$ by $- 3$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 3 x}{- 3} > \frac{- 6}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} > \frac{- 6}{- 3}$

Divide $x$ by $1$ .

$x > \frac{- 6}{- 3}$

Simplify the right side.

Divide $- 6$ by $- 3$ .

$x > 2$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x > 2$

Interval Notation:

$(2, \infty)$

Solve the Inequality for x x+3<4x-3

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