Evaluate square root of -36/(-1-3)

$\sqrt{\frac{- 36}{- 1 - 3}}$

Subtract $3$ from $- 1$ .

$\sqrt{\frac{- 36}{- 4}}$

Divide $- 36$ by $- 4$ .

$\sqrt{9}$

Rewrite $9$ as $3^{2}$ .

$\sqrt{3^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$3$

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