Find q(p(x)) p(x)=x^2+9 q(x) = square root of x+8

$p (x) = x^{2} + 9$ $q (x) = \sqrt{x + 8}$

Step 1

Set up the composite result function.

$q (p (x))$

Step 2

Evaluate $q (x^{2} + 9)$ by substituting in the value of $p$ into $q$ .

$q (x^{2} + 9) = \sqrt{(x^{2} + 9) + 8}$

Step 3

Add $9$ and $8$ .

$q (x^{2} + 9) = \sqrt{x^{2} + 17}$