Solve for x x1/(y^4)=2y^2+c

$x \frac{1}{y^{4}} = 2 y^{2} + c$

Combine $x$ and $\frac{1}{y^{4}}$ .

$\frac{x}{y^{4}} = 2 y^{2} + c$

Multiply each term in $\frac{x}{y^{4}} = 2 y^{2} + c$ by $y^{4}$ to eliminate the fractions.

Multiply each term in $\frac{x}{y^{4}} = 2 y^{2} + c$ by $y^{4}$ .

$\frac{x}{y^{4}} y^{4} = 2 y^{2} y^{4} + c y^{4}$

Simplify the left side.

Cancel the common factor of $y^{4}$ .

Cancel the common factor.

$\frac{x}{y^{4}} y^{4} = 2 y^{2} y^{4} + c y^{4}$

Rewrite the expression.

$x = 2 y^{2} y^{4} + c y^{4}$

Simplify the right side.

Multiply $y^{2}$ by $y^{4}$ by adding the exponents.

Move $y^{4}$ .

$x = 2 (y^{4} y^{2}) + c y^{4}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = 2 y^{4 + 2} + c y^{4}$

Add $4$ and $2$ .

$x = 2 y^{6} + c y^{4}$