Write in Standard Form (x^2-4x+3)+(3x^2-3x-5)

$(x^{2} - 4 x + 3) + (3 x^{2} - 3 x - 5)$

Step 1

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c$

Step 2

Add $x^{2}$ and $3 x^{2}$ .

$4 x^{2} - 4 x + 3 - 3 x - 5$

Step 3

Subtract $3 x$ from $- 4 x$ .

$4 x^{2} - 7 x + 3 - 5$

Step 4

Subtract $5$ from $3$ .

$4 x^{2} - 7 x - 2$